An unknown metal is dropped into 127 grams of water. the temperature of the water has been raised from 25 degrees c to 28 degrees c. using the specific heat of water , determine the amount of heat gained by the water.

Explanation:

Relation between heat energy, specific heat and temperature change is as follows.

                Q =

where,    Q or q = heat energy

              m = mass

              C = specific heat  = 4.186

          = change in temperature = =

Now, putting the given values into the above formula as follows.

             Q =

                 =

                 = 1594.86 J

or,             = 1.59 kJ           (as 1 kJ = 1000 J)

Therefore, we can conclude that the amount of heat gained by the water is 1.59 kJ.