Imagine that you heat a pot of water to a boil (212°F), then you turn off the stove and let the water sit there. The room is at room temperature (72°F) What temperature do you predict the water cool to after sitting for 8 hours? (

72 °F

Explanation:

Hello,

In this case, since matter tend the be stable at conditions they do not change, if we have water at room temperature (72 °F) and we heat it until boiling but then we turn off the stove, we molecularly see that due to the heat, the molecules start moving faster and crashing to each other; however when that fed energy starts being removed as the stove gets turned off, the molecules lose energy causing them to start moving slower so they lose energy until a point the remain at the initial status, that is 72 °F because thermal equilibrium is reached. Therefore it is likely for the water to be at 72 °F as well once 8 hours have passed, because a thermal equilibrium is reached with the environmetnal temperature.

Best regards.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.