15.0 L of an ideal gas at 298 K and 3.36 bar are heated to 350 K with a new pressure of 4.40 atm. What is the new volume in litres?

13.3 L

Explanation:

Step 1: Given data

Step 2: Convert P₁ to atm

We will use the conversion factor 1 atm = 1.01325 bar.

3.36 bar × (1 atm / 1.01325 bar) = 3.32 atm

Step 3: Calculate V₂

We will use the combined gas law.

P₁ × V₁/T₁ = P₂ × V₂/T₂

V₂ = P₁ × V₁ × T₂/T₁ × P₂

V₂ = 3.32 atm × 15.0 L × 350 K/298 K × 4.40 atm

V₂ = 13.3 L

i think 4.44 moles