0.05g of impure calcium carbonate was added in 20ml of N/5 (f= 1.05) HCL and the excess of hcl solution required 30 ml of N /10 (f= 1.15 ) NaoH for complete neutralization. Find the percentage purity of CaCo3 .

Ithink the answer is 56.

Answer//the law of conservation of mass.;

The reaction 2kalsi3o8 + 2(h+ + hco3-) + h2o  →  al2si2o5(oh)4 + 2k+ + 2hco3- + 4sio2 shows that feldspar kalsi3o8 is chemically altered by hydrolysis to form chalky-looking clay mineral kaolinite al2si2o5(oh)4. the chemical breakdown of potassium feldspar due to exposure to acidic water results to the mineral binding with the water molecule to become kaolinite with silica and potassium and bicarbonate ions in solution.