Ammonia ( NH3, MM 17.031 g/mol) and hypobromite ( OBr−) react according to the following chemical reaction. 2NH3+3OBr−⟶N2+3Br−+3H2O Suppose 0.325 g of ammonia reacts with 14.5 mL of a hypobromite solution. Calculate the concentration of the hypobromite solution.

1.98 M

Explanation:

Step 1: Write the balanced reaction

2 NH₃ + 3 BrO⁻⟶ N₂ + 3 Br⁻ + 3 H₂O

Step 2: Calculate the moles corresponding to 0.325 g of ammonia

The molar mass of NH₃ is 17.03 g/mol.

0.325 g × (1 mol/17.03 g) = 0.0191 mol

Step 3: Calculate the reacting moles of hypobromite

The molar ratio of NH₃ to BrO⁻ is 2:3. The reacting moles of hypobromite are 3/2 × 0.0191 mol = 0.0287 mol

Step 3: Calculate the molar concentration of the hypobromite solution

M = 0.0287 mol / 0.0145 L = 1.98 M

it's c. elements are placed in rows based on how may valencies electrons have.