The combustion of liquid octane C8H18, in the presence of gaseous oxygent yields carbon dioxide and liquid water. In determining how many moles of water are produced by the reaction of 1.50 moles of octane, which conversion factor should be used?

The answer to your question is given below.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

From the balanced equation above,

2 moles C8H18 reacted to produce 18 moles of H2O.

Finally, we shall determine the number of moles of H2O produced by the reaction of 1.5 moles of C8H18. This can be obtained as follow:

From the balanced equation above,

2 moles C8H18 reacted to produce 18 moles of H2O.

Therefore, 1.5 moles of C8H18 will react to produce = (1.5 × 18)/2 = 13.5 moles of H2O.

Thus, 13.5 moles of H2O were obtained from the reaction.

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