What is the approximate energy of a photon having a frequency of 4 x 10 ^7 Hz (E = vxh, h= 6.6x 10^-34 JxSec) *

E = 26.4 × 10⁻²⁷ j

Explanation:

Given data:

Frequency of photon = 4×10⁷ Hz

Energy of photon = ?

Planck's constant = 6.6 × 10⁻³⁴ js

Solution:

Formula:

E = h × v

v =  frequency

Now we will put the values in formula.

E = 6.6 × 10⁻³⁴ js × 4×10⁷ Hz

Hz = s⁻¹

E = 26.4 × 10⁻²⁷ j

The energy of photon is 26.4 × 10⁻²⁷ j.

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