A gaseous compound Y contains carbon and hydrogen only and has a density of 1.696 g dm-3 at 95.3 kPa pressure and 298K. Assume that Y behaves ideally,
calculate its molar mass and deduce its molecular formula. Given 1kPa =1 x 103Nm-2

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Explanation:

Hello.

In this case, knowing the temperature, density and temperature of Y which behaves ideally, we can write the ideal gas equation:

Whereas the moles are equal to the mass over the molar mass of Y:

Thus, solving for the molar mass we write:

Yet, since density is mass of over volume, we then write:

Considering the pressure in atm and the density in g/L:

Therefore, by plugging the values in, we obtain:

Thus, the gas may be propane () since it molar mass is 44.11 g/mol.

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