What will happen if we keep the metallic can in a water bath having cold water. Give reason

when a cold metallic is put in a water bath with cold water than the laws of thermodynamics and calorimetry suggests that both the solid and the liquid will engage in heat exchange until they attain equilibrium.

once they both are at equal temperature, no heat transfer will continue and the bodies will just stat in a packed atmosphere.

i think it is d. e because the next one is igneous.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm