An unknown sample is being evaluated in lab. What is the specific heat capacity of the compound if it requires 170.97raise the temperature of 54.07 grams of the unknown from 15.2 degrees * C to 33.5 °C.

Specific heat capacity =  0.173 j/g.°C

Explanation:

Given data:

Mass of sample = 54.07 g

Heat required = 170.97 j

Initial temperature = 15.2 °C

Final temperature = 33.5°C

Specific heat capacity = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 33.5°C - 15.2°C

ΔT = 18.3°C

170.97 j = 54.07 g × c ×  18.3°C

170.97 j = 989.48 g.°C  × c

c = 170.97 j /989.48 g.°C

c = 0.173 j/g.°C

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

20 drops hope this