Find the final temperature of the 10 g object with a sp. Heat of 1 cal/g o C and a heat content of 50 cal.
Its initial temperature is 20 degrees Celsius.

Final temperature of object = 25°C

Explanation:

Given data:

Final temperature of object = ?

Mass of object = 10 g

Specific heat capacity of object = 1 cal/g.°C

Heat content  = 50 cal

Initial temperature = 20°C

Solution;

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

Now we will put the values in formula.

50 cal = 10 g × 1 cal/g.°C  × (T2 - 20°C)

50 cal/ 10 cal/°C  =   (T2 - 20°C)

5 °C   =  (T2 - 20°C)

5°C + 20°C = T2

T2 = 25°C

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