Milk of magnesia, Mg(OH)2, is prepared from the reaction of aqueous magnesium sulfate and sodium hydroxide solution. If a solution containing 125 g of MgSO4 is added to a solution with 115 g of NaOH, what is the mass of milk of magnesia produced

Explanation:

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In this case, since the described chemical reaction between aqueous magnesium sulfate and sodium hydroxide is:

Whereas can see a 2:1 mole ratio between sodium hydroxide and magnesium sulfate whose molar masses are 120.366 g/mol and 39.997 g/mol. Next step, is to compute the yielded moles of milk of magnesia yielded by both 125 g of magnesium sulfate (1:1 mole ratio) and 115 g of sodium hydroxide (2:1 mole ratio):

Thus, since magnesium sulfate yields less moles of milk of magnesia than sodium hydroxide, we infer that MgSO4 is the limiting reactant so the yielded mass of milk of magnesia (58.320 g/mol) is:

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hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.