6. (03.04 MC) What is the name of N2Cl4? Explain how you determined the bond type and the steps you used to determine the naming convention for the compound. (5 points)

See explanation

Explanation:

First of all, we must remember that this compound bears a striking similarity to N2H4 (hydrazine). It must be a chlorine analogue of hydrazine.

Hydrazine is a covalent molecule, hence N2Cl4 must also be a covalent compound. It is formed by the reaction; N2 + 2Cl2 → N2Cl4 and is trivially called tetrachlorohydrazine. Generally, hydrazines contain the N-N  single bond in inorganic compounds.

Systematically, the name is dinitrogen tetrachloride because it contains two nitrogen atoms directly bonded to each other. Each of the nitrogen atoms is bonded to two other chlorine atoms making a total of four chlorine atoms in the molecule.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"