2090 J of heat energy are removed from 40 g of a silvery metal at 81.7°C. The temperature falls to 30°C. According to the chart below which metal would it most likely be? (Show work!) METAL. SPECIFIC HEAT (J/goC) -aluminum = 0.90 -magnesium = 1.01 -silver = 0.234 -tin = 0.220 -zinc = 0.386

Magnesium would be the metal

Explanation:

The heat involved in a physicochemical process follows the formula:

Q = m×C×ΔT

Where Q is heat involved,

m is mass of substance,

C is specific heat of the susbtance

And ΔT change in temperature

We can solve por specific heat of the solution:

C = Q / m*ΔT

Replacing the values of the problem:

C = 2090J / 40g*(81.7°C-30°C)

C = 1.01J/g°C

This specific heat is the specific heat of Magnesium. Thus:

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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