Using the balanced chemical equation below, calculate the moles of carbon dioxide, CO2, produced by the complete decomposition of 1.75 moles of calcium carbonate, CaCO3

1.75 mol CO₂

Explanation:

Step 1: Given data

Moles of calcium carbonate: 1.75 mol

Step 2: Write the balanced decomposition reaction

CaCO₃ ⇒ CaO + CO₂

Step 3: Calculate the moles of carbon dioxide produced from 1.75 moles of calcium carbonate

The molar ratio of CaCO₃ to CO₂ is 1:1. The moles of CO₂ produced are:

1.75 mol CaCO₃ × (1mol CO₂/1 mol CaCO₃) = 1.75 mol CO₂

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally