Antimony pentafluoride has a formula of SbF5. What is the percent composition of Sb in this molecule

56.17% is percent composition of Sb in the molecule

Explanation:

Percent composition is the percent in mass of each element present in a particular molecule.

In SbF₅, there is 1 mole of Antimony -Molar mass: 121.76g- per 5 moles of fluorine -Molar mass: 19g/mol-. In a basis of 1 mole, the mass of Sb and F is:

Mass Sb:

1mol * (121.76g/mol) = 121.76g

Mass F:

1 mol SbF₅ = 5 moles F * (19g / mol) = 95g

Total mass:

121.76g + 95g = 216.76g

And percent composition of Sb:

121.76g / 216.76g * 100 =

it is a solid

explanation:

c

explanation: