How many grams of heptane are needed to completely react with 106 g of O2?

21.9g

Explanation:

The balanced reaction for the combustion of heptane is;

C7H16 + 11 O2 > 7 CO2 + 8 H2O

from the balanced reaction,

1 mole of heptane = 11 moles of O2

converting to mass

100g of Heptane = 484g of O2

xg of Heptane = 106g of O2

x = 106×100/484

x = 21.9g

Therefore, 21.9g of heptane is needed to completely react with 106 g of O2

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