In the following balanced chemical equation, if 115.0g of oxygen reacts with 32.5g of methane, CH4, which is the limiting reactant, and how much of the excess reactant is left? CH4 + 2O2 → CO2 + 2H2O
a. methane is limiting with 3.68g of oxygen left
b. methane is limiting with 79.08 g of oxygen left
c. methane is limiting with 1.80g of oxygen left
d. oxygen is limiting with 3.68g of methane left
e. oxygen is limiting with 2.03g of methane left

Answer asap need it by wednesday morning carry out the following calculations on ph and ka of from data. i. calculate the ph of 0.02m hcl ii. calculate the ph of 0.036m naoh iii. calculate the ph of 0.36m ca(oh)2 iv. calculate the ph of 0.16m ch3cooh which has ka = 1.74 x 10-5 mol dm-3 v. calculate ka for weak acid ha which has a ph of 3.65 at 0.30m concentration vi. calculate the ka of a solution made by mixing 15.0 cm3 0.2m ha and 60.0 cm3 0.31m a-. [ph= 3.80] vii. calculate the ph of a solution made by mixing 15.0 cm3 0.1m naoh and 35.0 cm3 0.2m hcooh. [ka = 1.82 x 10-4 m]