An excess of oxygen reacts with 451.4 g of lead, forming 374.7 g of lead(II) oxide. Calculate the percent yield of the reaction.

The percent yield of the reaction is 77.0 %

Explanation:

According to stoichiometry:

2 moles of produces = 2 moles of

2.18 moles of is produced by= of

Mass of =

percent yield =

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

where's the diagram?