A mixture of 40 mol % isopropanol in water is distilled at 1 atm by differential distillation until 70 mol % of the charge has been vaporized (equilibrium data are given in Exercise 7.33). What is the composition of the liquid residue in the still pot and of the collected distillate

Explanation:

From the given information:

The percentage wieght of mixture = 0.4

The distillate = 70

From equilibrium data in Exercise 7.33

The Feed W = 100

The Liquid residue F = Feed(W) - Distillate (D)

= 100 - 70 = 30

By applying rayleigh equation;

From the plot of the graph of ; the area under the curve is being calculated between the point { }.

Such that; the area = 1.209

Similarly, the value of xF = 0.067

∴

the right answer is c i just did the question.