1. Assume alpha decay occurs on the following isotopes. What atomic mass, atomic number, and atomic symbol will the product have?
a. Silicon-28
i. Mass:
II. Number:
Symbol:

Explanation:

Given parameters:

   Isotope ;

           Si - 28

           ²⁸₁₄Si;

The specie undergoes an alpha decay; An alpha particle resembles a helium atom;

           ²⁸₁₄Si   →  ⁴₂He  +   ?

In nuclear reactions, the mass and atomic numbers are usually conserved;

   So let specie unknown be denote as X

          ᵃₙX;

           ²⁸₁₄Si   →  ⁴₂He  +   ᵃₙX

Sum of the mass number on the reactant side must equal to that on the product side;

         28  = 4 + a

         28 - 4  = a

               a  = 24  mass number of X;

   14  = 2 + n

   n = 14 - 2  = 12   atomic number of X;

 Now, the species X with an atomic number of 12 is magnesium

  Symbol is Mg

   Mass number   = 24

the answer is definitely c.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.