How many moles of acetaminophen are in a 0.8mL (0.0008L) dose of infants Tylenol

0.007 mol

Explanation:

Step 1: Given data

Volume of acetaminophen: 0.8 mL

Step 2: Calculate the mass corresponding to 0.8 mL of acetaminophen

The density of acetaminophen is 1.26 g/mL.

0.8 mL × (1.26 g/mL) = 1 g

Step 3: Calculate the number of moles corresponding to 1 g of acetaminophen

The molar mass of acetaminophen is 151.16 g/mol.

1 g × (1 mol/151.16 g) = 0.007 mol

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)