vacuum line is lowered to a pressure of 1.3kpa and 77 k find the number of moles per mm3. Assume that R= 8.31 JK-1 mol-1

The number of moles per mm³=2.032 x 10⁻⁹

In general, the gas equation can be written  

where  

P = pressure, atm , N/m²

V = volume, liter  

n = number of moles  

R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8.314 J/mol K (P=Pa or N/m2, v= m³)

T = temperature, Kelvin  

P=1.3 kPa=1.3.10³ N/m²

T = 77 K

R = 8.31 J/mol.K

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation: