A sample of laughing gas occupies 0.250 L at 14.7 psi and - 80.0°C. If the volume of the gas is 0.375 L at 25.0°C, what is the pressure?

Final pressure =P₂ = 15.13 psi

Explanation:

Given data:

Initial volume = 0.250 L

Initial pressure = 14.7 psi

Initial temperature = -80.0°C (-80.0 +273 = 193 K)

Final volume = 0.375 L

Final temperature = 25.0°C (25+273 =298 k)

Final pressure = ?

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 14.7 psi × 0.250 L × 298 K / 193 K × 0.375 L  

P₂ = 1095.15 psi .L. K / 72.375 K.L

P₂ = 15.13 psi

the answer is:  

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