A gas expands from 285 mL to 789 mL at constant temperature. How much work is done by the gas (joules) if it expands against a constant pressure of 6.00 atm?

-306j

Explanation:

For this question we define an equation:

W = -Pext(Vj-Vi)> eqn 1

P = 6atm

Vi = 285 ml

We convert it to litre

= 285/1000 mL

= 0.285 L

Vj = 789 mL

When converted to litre

= 789/1000 mL

= 0.789 L

These values are all going to be put values in the eqn 2 above

W = -Pext(Vj-Vi)

W = -6.0x (0.789L - 0.285L)

W = -3.024

W = -3.024 x 101.33 J

This gives us the answer

W = -306 J

Thank you!

-306 J

sodium (na), for example, has one electron in its valence shell. this is an unstable state because that valence shell needs eight electrons to be full. in order to fill its valence shell, find a way to add seven electrons to its valence shell