Ik its confusing so you can just go to the pdf 1. Which letters show the balls with the maximum potential energy? A D E G 2. Which letter shows the ball with the maximum kinetic energy? B C D G 3. Which letters show the balls with the least kinetic energy? A B F G 4. Which letter shows the ball with the least potential energy? C D E G 5. Which letters show the balls with a little less kinetic energy than ball C? A B D F 6. Which letters show the balls with a little more potential energy than ball D? C D E F 7. Which letters show the balls with a little more potential energy than ball F? A C E G 8. Which letters show the balls with a little less potential energy than ball G? A B F G 9. Which letter shows the ball with a little more kinetic energy than ball C? B C D F 10. Which letter shows the ball with a little less potential energy than ball E? B D E F 11. What TWO things decide the amount of kinetic energy an object can have? 12. Name two other things that can show kinetic and potential energy in action.

1 A

2 C

3 G

4 D

5 E

6 A and G

7 D and E  

8 F

9 B

10 C

11 if it is in motion and how much motion it has

12 a bow being pulled back shows potential and dropping a ball can chow kinetic

IM SO SRRY  don't feel bad

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.