How many water molecules are generated when 3.60 moles of ammonia react according to the following equation: 3PbO+2NH3→3Pb+N2+3H2O

Use 6.022×1023mol−1 for Avogadro's number.
Your answer should have three significant figures.

3.25 × 10²⁴ molecules of water

Explanation:

Step 1: Write the balanced equation

3 PbO + 2 NH₃ → 3 Pb + N₂ + 3 H₂O

Step 2: Calculate the moles of water formed from 3.60 moles of ammonia

The molar ratio of NH₃ to H₂O is 2:3. The moles of water formed are 3/2 × 3.60 mol = 5.40 mol

Step 3: Calculate the molecules in 5.40 moles of water

We will use Avogadro's number: 6.022 × 10²³ molecules/mol.

5.40 mol × 6.022 × 10²³ molecules/mol = 3.25 × 10²⁴ molecules

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

i believe the answer is a.