Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3+3H2SO4âAl2(SO4)3+6H2O. Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react?How many moles of Al2(SO4)3 can form under these conditions? How many moles of the excess reactant remain after the completion of the reaction?

Explanation:

2Al(OH)₃   +   3H₂SO₄  =    Al₂(SO₄)₃   +   6H₂O

2 moles         3 moles  

2 moles of Al(OH)₃ reacts with 3 moles of H₂SO₄

.55 moles of Al(OH)₃ reacts with .55 x 1.5  moles of H₂SO₄

moles of H₂SO₄ required =   .825 moles

moles available = .55 moles , so  H₂SO₄ is the limiting reagent .

3 moles of  H₂SO₄ yields 1 moles of Al₂(SO₄)₃

.55 moles of  H₂SO₄ yields 1 x .55 / 3  moles of Al₂(SO₄)₃

Al₂(SO₄)₃ produced = 1 x .55 / 3  moles = .1833 moles .

Al(OH)₃  reacted = 2 x .55 / 3 = .367 moles

excess Al(OH)₃ remaining = .5 - .367

= .133 moles .

answer is: naturally occurring solid, inorganic compound or element is mineral.

minerals usually have crystalline form, that means than crystal constituents (atoms, molecules or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

for example magnetite is a mineral of iron oxide (fe₂o₃).

calcite is a carbonate mineral and the most stable polymorph of calcium carbonate (caco₃).

dolomite is an   carbonate mineral composed of calcium magnesium carbonate (camg(co₃)₂).

gold is my favorite solid.