What is the solubility in moles/liter for calcium phosphate at 25°C given a Ksp value of 1.2 x 10^-29. Write using scientific notation and use 1 or 2 decimal places.

Explanation:

Ca₃( PO₄)₂ = 3 Ca⁺² + 2 PO₄⁻³

x                      3x            2 x

Let solubility be x mole per litre

solubility product = (3x )³ x ( 2x )²

= 108 x⁵ = 1.2 x 10⁻²⁹

x⁵ = .0111 x 10⁻²⁹ = .111 x 10⁻³⁰

x = .64 x 10⁻⁶ moles / litre

the answer is 0.8m.

by: nicholas