Calculate the number of joules needed to change 20.0 g of ice at 0.00 °C to liquid water at 42.8 °C

7509.6j

Explanation:

I asked if the temperature of the ice but since it doesn't that means the temperature of the ice is at 0°c and latent heat of fusion [ML] will take place when it changes to water at 0°c also, then the temperature of the water rises to 10°c MCΘ will be used.

Now in the application, using the formula;

mL+MCΘ

Where;

m=20    L=334     M=4.148    Θ=10

Inputting the values we should have;

334×20+4.148×20×10

6680+829.6

7509.6j

the answer is minerals.