The specific rotation of (S)-2- butanol is + 13.5. If 1.00 g is dissolved in 10.0 mL of ethanol and placed in a sample cell with a length of 1.00 dm, what observed rotation do you expect?

-1.35 degree

Explanation:

Given the specific rotation of (S)-2-butanol = +13.5 degree

So, the specific rotation of its enantiomer (R)-2-butanol = -13.5 degree

Now the optical rotation of a pure liquid is given by

Here,  = the optical rotation

          = specific rotation at temperature 't' and wave length 'λ'

                = -13.5 degree

         l = optical path length

           = 1 dm

          d  = density

             = 1/10

Therefore,

    = -1.35 degree

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.