If 2.50g of CuSO4 is dissolved in 8.95 x 10^2 mL of 0.300 M NH3, calculate the concentrations of the following species at equilibrium: Cu^2+, NH3, Cu(NH3)4^2. I tried to solve and came up with the following-

Cu^2+ = 1.1149x10^-13 (Which was all wrong except for the 10^-13)

NH3 = .230 (Which was correct)

Cu(NH3)4^2+ = 0.069720 (Which was wrong)

Can someone please show me where I am going wrong.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.