For the following reaction: N2 + 3H2 -> 2NH3
What mass of NH3 can be produced from 14.9g N2 and 3.8 g H2 ?

Nitrogen is the limiting reactant, and  

3.74

grams of ammonia is formed.

Explanation:

We have the familiar Haber process equation...

N

2

(

g

)

+

3

H

2

(

g

)

⇌

2

N

H

3

(

g

)

Since the mole ratio of  

N

2

to  

H

2

is  

1

:

3

, then for every mole of nitrogen, we would need three moles of hydrogen.

Explanation:

the right answer is c i just did the question.