a balloon initially has 0.40 liters and a temperature of 20°C what will the volume of the balloon be after it heats to 250°C

0.7L

Explanation:

Given parameters:

Initial volume V₁  = 0.4L

Initial temperature T₁  = 20°C  = 20 + 273  = 293K

Final temperature  = 250°C  = 250 + 273  = 523K

Unknown:

Final volume V₂ = ?

Solution:

To solve this problem, we apply Charles's law.

It states that "the volume of a fixed mass of a gas varies directly as the absolute temperature if the pressure is constant".

 mathematically;

V and T are temperature values

1 and 2 are initial and final states;

  Insert the parameters and solve;

      =  

        V₂   =   = 0.7L

j

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml