What is the mass of 2.23 x 1023 atoms of sulfur?

11.9 g S

General Formulas and Concepts:

Chem

Explanation:

Step 1: Define

2.23 × 10²³ atoms S

Step 2: Define conversions

Avogadro's Number

Molar Mass of S - 32.07 g/mol

Step 3: Dimensional Analysis

= 11.8758 g S

Step 4: Check

We are given 3 sig figs. Follow sig fig rules.

11.8758 g S ≈ 11.9 g S

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole