A latex balloon will adjust to maintain the same pressure. If the balloon is filled with 19.4 L of helium initially at 25.2 degrees Celcius, what would the volume be if the temperature adjusted to 5.4 degrees Celcius?

V₂ =18.11  L

Explanation:

Given data:

Initial volume = 19.4 L

Initial temperature = 25.2°C (25.2+273 =298.2 K)

Final volume = ?

Final temperature = 5.4°C ( 5.4+273 =278.4K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 19.4 L × 278.4 K / 298.2 k

V₂ = 5400.96 L.K / 298.2 K

V₂ =18.11  L

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