A 15.0 mL solution of Sr(OH)2 is neutralized with 38.5 mL of 0.350 M HCI. What is the concentration of the original Sr(OH)2 solution?

The required molarity of 15.0 mL solution is 0.449 M and the further calculation can be defined as follows:

Given that:

Volume of solution = 15.0 mL

n-factor of solution = 2

Molarity of HCl solution = 0.350 M

Volume of HCl solution = 38.5 mL

n-factor of HCl solution = 1

To find:

Molarity of solution required.

Formula used to calculate the molarity of solution is:

where, are the n-factor, molarity and volume of acidic solution while are the n-factor, molarity and volume of basic solution.

Put the values in the above formula:

So, the required molarity of solution is 0.449 M.

Learn more about neutralization reaction: link

Molarity of Sr(OH)₂  = 0.47 M

Explanation:

Given data:

Volume of Sr(OH)₂ = 15.0 mL

Volume of HCl = 38.5 mL (0.0385 L)

Molarity of HCl = 0.350 M

Concentration/Molarity of Sr(OH)₂  = ?

Solution:

Chemical equation:

Sr(OH)₂ + 2HCl     →      SrCl₂ +2H₂O

Number of moles of HCl:

Molarity = number of moles/ volume in L

0.350 M = number of moles/0.0385 L

Number of moles = 0.350 mol/L× 0.0385 L

Number of moles = 0.0135 mol

Now we will compare the moles of HCl with Sr(OH)₂.

                    HCl       :     Sr(OH)₂

                      2         :         1

                   0.0135   :      1/2×0.0135 = 0.007 mol

Molarity/concentration of Sr(OH)₂:

Molarity = number of moles / volume in L

Molarity = 0.007 mol /0.015 L

Molarity = 0.47 M

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >