Iron reacts with oxygen gas to produce iron (III) oxide. If there are 52 grams of iron present in this reaction how many grams of iron (III) oxide are produced
assuming a 100% yield? Also how many liters of oxygen are needed assuming
STP conditions?

Mass of Fe₂O₃ : 74.26 g

Volume of O₂ at STP = 15.624 L

Reaction

4Fe (s) + 3O₂ (g) ==> 2Fe₂O₃ (s)

mol Fe :

Ar Fe = 56 g/mol

mol Fe₂O₃ :

mass Fe₂O₃ :

MW Fe₂O₃ : 159,69 g/mol

mol O₂ :

volume O₂ at STP(1 mol=22.4 L)

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023