Hydrogen gas is bubbled into a solution of barium hydroxide that has sulfur in it. The unbalanced equation for the reaction that takes place is: H2+S+OH- —-> S2- + H2O What volume of 0.258 M Ba(OH)2 is required to react completely with 3.00g sulfur?

Volume of Ba(OH)₂ : 0.363 L

Further explanation

Balanced equation :

H₂(g)+S(s)+2OH⁻(aq)⇒ S²⁻(aq)+2H₂O(l) (eq 1)

Ba(OH)₂⇒Ba²⁺+2OH⁻ (eq 2)

mol S :

mol OH from eq 1 : (mol S : mol OH = 1 : 2)

mol Ba(OH)₂ from eq 2 : (mol Ba(OH)₂ : mol OH⁻=1 : 2)

volume of Ba(OH)₂ :

Inot sure what it is i sorry : ((

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