A gas balloon has a volume of 106.0 liters when the temperature is 45.0 °C and the pressure is 740.0 mm of mercury. What will its volume be at 20.0 °C and 780 .0 mm of mercury pressure?

New volume V2 = 92.7 Liter (Approx)

Explanation:

Given:

V1 = 106 l

T1 = 45 + 273.15 = 318.15 K

P1 = 740 mm

T2 = 20 + 273.15 = 293.15 K

P2 = 780 mm

Find:

New volume V2

Computation:

P1V1 / T1 = P2V2 / T2

(740)(106) / (318.15) = (780)(V2) / (293.15)

New volume V2 = 92.7 Liter (Approx)

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

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the answer would be a