Urea, which has the chemical formula (NH2)2CO, is a fertilizer that can be prepared by reacting ammonia (NH3) with carbon dioxide (CO2). Given the following chemical equation, what is the theoretical yield of urea (in grams) if 3.57 mol ammonia is the limiting reactant

answer: lol

explanation:

lol

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i believe it is c.) 1575 j.

the answer is 1 i believe