HCI + NaOH --> NaCl + H 20 3g +
? ?-> 4 + 2 2
How many grams of NaOH is required in the reaction?
O 6 grams
O 9 grams
O 4 grams
O 3 grams

option D is correct

Explanation:

no of moles in 3 grams of HCL=3/36=0.08

if 1 mole of HCL require 1 mole of NaOH then 0.08 moles required 0.08 moles of NaOH

mass of 0.08 moles of NaOH=moles*molar mass=0.08*40=3.2 grams

so 3 grams are required in the reaction

lol idk man i guess u gotta ask bill nye the science guy

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3