What is the energy photon with a frequency of 2.22 x 10^14 1/s ?

1.47 x 10⁻¹⁹J

Explanation:

Given parameters;

Frequency of wave  = 2.22 x 10¹⁴/s

Unknown:

Energy of the photon = ?

Solution:

The energy of a photon can be mathematically derived using the expression below;

        E = hf

  E is the energy

 h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

 f is the frequency  

Insert the parameters and solve;

 E = 6.63 x 10⁻³⁴m²kg/s x  2.22 x 10¹⁴/s  

 E = 14.7 x 10⁻²⁰J or 1.47 x 10⁻¹⁹J

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