What is the empirical formula of a compound composed of 34.5 g potassium (k) and 7.06 g oxygen (o)?

Atomic mass : 

K = 39.09 a.m.u
O = 15.99 a.m.u

number of moles:

K = 34.5 / 39.09 => 0.882 moles of K
O = 7.06 / 15.99 => 0.441 moles of O

Use the least number of moles obtained to get the formula empirical:

K = 0.882 / 0.441 => 2
O =  0.441 / 0.441 => 1

Therefore  :  K₂O

 hope this helps!

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