Calculate the mass of fe(no3)3 that is measured to prepare 500.0 mL of a 0.175mol/L solution.

21.3g

Explanation:

The formula of the compound is;

        Fe(NO₃)₃

Given:

volume  = 500mL  = 0.5L

concentration  = 0.175mol/L

Unknown:

Mass of  Fe(NO₃)₃ measured = ?

Solution:

To solve this problem, find the number of moles first;

      Number of moles of  Fe(NO₃)₃ = concentration x volume

 So;

      Number of moles  = 0.175 x 0.5   = 0.088mol

Now to find the mass;

  Mass  = number of moles x molar mass

      Molar mass of  Fe(NO₃)₃ = 55.8 + 3[14 + 3(16)]

       Molar mass of  Fe(NO₃)₃ = 55.8 + 3(62) = 241.8g/mol

  Mass = 0.088mol x 241.8g/mol  = 21.3g