The specific heat of a substance is 0.38 J/goC. How much energy is required to raise the temperature of 42 g of the substance from 25oC to 39oC?

223.4J

Explanation:

Given parameters:

Specific heat capacity of substance  = 0.38J/g°C

Mass of substance  = 42g

Initial temperature  = 25°C

Final temperature  = 39°C

Unknown:

Energy required to raise the temperature  = ?

Solution:

The amount of heat required by the substances can be derived using the expression below;

  H  = m c Δt

H is the amount of heat energy

m is the mass

c is the specific heat capacity

Δt is the change in temperature;

 Δt  = 39°C  -  25°C  = 14°C

 Now insert the parameters and solve;

 H = 42 x 0.38 x 14  = 223.4J

the answer is d.) potassium