Hi Jose, when you submit this form, the owner will be able to see your name and email address. 1. A 100. g samle of water absorbs how many Joules of energy as its temperature is changed from
35.0 C to 60.0 C. (water s = 4.184 J/g C)

10460J

Explanation:

Given parameters:

Mass of water sample  = 100g

Initial temperature = 35°C

Final temperature  = 60°C

Unknown:

Amount of energy absorbed by water = ?

Solution:

The amount of energy absorbed by water is mathematically expressed below;

    H  = m C ΔT

H is the amount of energy

m is the mass

C is the specific heat capacity of water  = 4.184J/g°C

ΔT  = 60°C  - 35°C  = 25°C

 Now insert the parameters and solve;

 H = 100 x 4.184 x 25  = 10460J

so what is the problem with your lab report and whats the subject of the lab report? i will you