If 52 j of heat is added to an aluminum can with a mass of 28.4 g , what is its temperature change? specific heat capacity of aluminum is 0.903 j/g∘c.

We can use the heat equation,

Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (g), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

The given data

  Q = 52 J

  m = 28.4 g

   c = 0.903 J g⁻¹ °C⁻¹

 ΔT = ?

By applying the formula,

  52 J = 28.4 g x 0.903 J g⁻¹ °C⁻¹ x ΔT

    ΔT = 2.03 °C

Hence, the temperature change of aluminium during the heating process is 2.03 °C.

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.