How many grams of H2SO4 are needed to react with 78.86 grams of AI(NO3)3 ?
I

53.18 grams of H₂SO₄ are needed to react with 78.86 grams of Al(NO₃)₃.

Explanation:

The balanced reaction between Al(NO₃)₃ and H₂SO₄ is:

2 Al(NO₃)₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 HNO₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reagents are required:

Being the molar mass of the elements:

then the molar mass of the reactants are:

Then, by reaction stoichiometry, the following reagent mass amounts are required:

Then you can apply the following rule of three:  If by stoichiometry 436 g of Al(NO₃)₃ react with 294 g of H₂SO₄, 78.86 g of Al(NO₃)₃ with how much mass of H₂SO₄ will it react?

mass of H₂SO₄=53.18 g

53.18 grams of H₂SO₄ are needed to react with 78.86 grams of Al(NO₃)₃.

it should be all of them because it asks if you included all of those in your answer

explanation:

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.