For the reaction: C2H6 +
02 → CO2 +
H20
How many grams of CO2 are produced for each 8.00 grams of H20 produced?

Explanation:

no of moles of water=8.00/18=0.4

1 mole of C2H6 produced 1 mole of CO2 and 1 mole of H2O

so  for 1 mole of H2O 1 mole of CO2 is produced therefore for 0.4 mole of H2O 0.4 mole of CO2  is produced

now 0.4 mole of CO2 contain how much grams=0.4*44=17.6grams

but complete combustion of 2 mole of ethane produce 4 mole of CO2 and 6 moles of H2O

so  for 6 mole of H2O 4 mole of CO2 is produced therefore  for 0.4 moles of H2O 0.27 moles of CO2 is produced

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%